5=mn/k^2

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Solution for 5=mn/k^2 equation: 


10*(1/2)*R = 0

(2/3)*x-1 = (7/9)*x

(3/5)*(4*k-1) >= (5/3)*(3*k-2)

(((-2*u)^2)/v)^5 = 0

(6*x-3)/7-((3*x-8)/9) < -3

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